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CableCalcBS7671 · NFC · IEC
Guide

BS7671 Cable Sizing, Explained

The full method BS7671:2018+A2 uses to size a cable — design current, correction factors, current rating, voltage drop and the adiabatic check — with a worked calculator at each step.

The five checks BS7671 requires

Cable sizing to BS7671 isn't a single lookup — it's a sequence of checks that all have to pass simultaneously. Get any one of them wrong and the "correct" size from the others is still non-compliant. This guide walks through each step in order, the way BS7671:2018 Amendment 2 Appendix 4 and Section 525 define it.

1. Determine the design current, Ib

Ib is the current the circuit actually needs to carry under normal load — read directly from equipment ratings, calculated from kW and voltage for resistive loads (Ib = P / V for single-phase), or derived from motor nameplate data with efficiency and power factor for motor circuits.

2. Select the protective device, In

Choose an MCB, MCCB, fuse or RCBO with a standard rating at or above Ib. BS7671 Regulation 433.1.1 requires Ib ≤ In.

3. Read the tabulated rating, It

Using BS7671 Appendix 4, look up the tabulated current-carrying capacity for the cable's insulation (PVC 70°C or XLPE 90°C), configuration (multicore or single-core) and installation reference method (A1 through G — see the full tables). This figure assumes ideal conditions: 30°C ambient, installed alone, no thermal insulation contact.

4. Apply the correction factors to get Iz

Real installations rarely match those ideal conditions, so four factors correct It down to the actual current-carrying capacity, Iz:

  • Ca — ambient temperature, if not 30°C
  • Cg — grouping, if the cable shares a route with other loaded circuits
  • Ci — thermal insulation, if the cable is in contact with insulation
  • Cc — protective device type (only BS3036 semi-enclosed fuses need a factor below 1.00)

Iz = It × Ca × Cg × Ci × Cc, and Regulation 433.1.1 requires In ≤ Iz — combined with step 2, the full chain is Ib ≤ In ≤ Iz.

5. Check voltage drop

Independently of current rating, BS7671 Section 525 limits voltage drop to 3% of nominal voltage for lighting circuits and 5% for others, calculated from the cable's mV/A/m figure, its length and the design current. See the voltage drop calculator for the full method — this is frequently what actually decides the final cable size on longer runs, not the current rating.

6. Check the adiabatic (short-circuit) withstand

If a prospective fault current is available, Regulation 543.1.3 requires the minimum conductor size to satisfy S = (I × √t) / k, where I is the fault current, t is the protective device's disconnection time, and k is a material and insulation constant (143 for copper XLPE, 115 for copper PVC, 76 for aluminium, per Table 54.4). This step needs fault-level data that a quick sizing tool doesn't collect — it's covered in the full calculator.

BS7671:2018+A2
Size the cable
Design current Ib (A)
Device rating In (A)
Cable length (m)
Supply
Installation method
Insulation
Ambient temp (°C)
Circuits in group

Try the sequence above on your own circuit — enter Ib, In, length and installation method.

Minimum compliant size
10 mm²
Copper · XLPE · multicore · method C
Compliant
Tabulated It73.0 A
Derated Iz73.0 A
Voltage drop6.93 V (1.73%)
Vd limit (5%)20.00 V
Ca ambient1.00
Cg grouping1.00
Ci insulation1.00
Combined factor1.000

Iz = It × Ca × Cg × Ci × Cc. Voltage drop uses the mV/A/m figures from BS7671 Appendix 4 and is checked against the 5% limit in Section 525 for non-lighting circuits. Adiabatic and fault-level checks need a prospective fault current — use the full calculator for those.

Full calculator — fault current, PDF export
Questions

Frequently asked